Indiana Earns No. 3 Seed in Big Ten Tournament

ROSEMONT, Ill. - For the first time since 2012, the Indiana Baseball team (30-22-1, 15-9 B1G) will meet in-state rival Purdue in the Big Ten Tournament Presented by IFS.ai. IU, the number three seed, will meet No. 6 Purdue in the tournament's first game on Tuesday (May 21) morning at 11:00 AM ET/10:00 AM CT.

The two teams played the first weekend of May at Alexander Field in West Lafayette with the Hoosiers winning the final two games of the series. The Sunday contest featured a wild four-run ninth inning that helped IU to a comeback win and series victory over the Boilermakers.

Purdue (2012) and IU (2013-14) won every Big Ten Tournament title for a three-year span but neither team has won it since. These two rivals will be on the same side of the bracket as No. 2-seed Nebraska and No. 7-seed Ohio State at Charles Schwab Field in Omaha.

The winner of Tuesday's opening game will head to the winner's bracket and will be off until Thursday afternoon. The loser will have to come back and play an elimination game on Wednesday (May 22) evening. All games at this week's tournament in Omaha will be broadcasted on the Big Ten Network.

Indiana University Athletics

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